You can verify the zeros of the function by using a graph and finding where the graph y=x^+6x-7 A. is at a minimum B. is at a maximum C. crosses the x-axis D. crosses the y-axis
was there supposed to be something after the x ? y=x^?????+6x-7
^2
http://www.wolframalpha.com/input/?i=plot+y%3Dx^2%2B6x-7 plot the graph ... if you don't want, put y=0 and find the root's of the rest ... check if they are equal or real and different or imaginary
here's your graph. http://www.mathway.com/graph_image.aspx?p=y=x^2+6x-7?p=520?p=450?p=False?p=False?p=False?p=False?p=True?p=True?p=True?p=True?p=?p=?p=?p=?p=4
x^2+6x-7 = 0 , find x ... http://www.wolframalpha.com/input/?i=0%3Dx^2%2B6x-7 you can check the nature of roots by it's determinant 6^2 - 4 (1) (-7) > 0 ... which means you have two distinct roots => crosses y axis!!
A sexy person asking a math question... rare.
ahhahah
download a great graphing/geometry package called geogebra http://www.geogebra.org/cms/ it will meet all your graphing needs
put y = 0 to find the points where it crosses x axis
Else plot the parabola to check your answers
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