Question

A catapult launches a boulder with an upward velocity of 112 ft/s. The height of the boulder, h, in feet after t seconds is given by the function .
How long does it take the boulder to reach its maximum height? What is the boulder’s maximum height? Round to the nearest hundredth, if necessary. h=-16t^2+112t+30
A. 7 s; 30 ft
B. 3.5 s; 366 ft
C. 3.5 s; 618 ft
D. 3.5 s; 226 ft

Answer 1

Find the derivative ... Equate it to zero

Answer 2

t = 3. 5

Answer 3

put the value of t in h= .......................

Answer 4

and say thanks if you want XD

Answer 5

ok i got 358.4 and thanks

Answer 6

that's right

Answer 7

Hmm.. isn't the MAX H = 226 ?

Answer 8

T = 3.5 and H = 226

Answer 9

so (D)???????????