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How do I integrate the following using the by parts technique: x(X+1)^0.5
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\[\int\limits {x\sqrt {x+1}dx}\]
Why do you need use integration by parts here?
Thats what the question asks for...
\[\int\limits x \sqrt{x + 1} dx = \int\limits x\left(x + 1\right)^{\frac{1}{2}}dx\]\[u = x\]\[du = dx\]\[dv = \left( x + 1 \right)^{\frac{1}{2}}dx\]\[v = \frac{2}{3}\left( x + 1 \right)^{\frac{3}{2}}\]\[\int\limits u dv = uv - \int\limits v du\]\[\int\limits x \left( x + 1 \right)^{\frac{1}{2}} dx = \frac{2}{3}x \left( x + 1 \right)^{\frac{3}{2}}- \int\limits \frac{2}{3}\left( x + 1 \right)^{\frac{1}{2}}dx\]continue to integrate the right side
Thanks for that - much appreciated
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