Let f be the function given by f(x) = e^x/2 Find the first three nonzero term and the general term around 0 for (e^x/2)-1)/x Use it to find g'(2) and use it to show that
\[\sum_{n=0}^{\infty} n/ 4(n+1)! = 1/4\]
I actually found the first three nonzero terms but don't understand the second part.
Help please!
Is it \[ \frac{ e^x} 2 \]
What is g(x)?
g(x) is the ((e^x/2 )-1)/x
take the derivative of \(\frac{e^{\frac{x}{2}}-1}{x}\) i think is the first step,then replace x by 2
derivative evaluated at 2 will give you \(\frac{1}{4}\) which means that the expansion evaluated at two (that infinite sum you have in the question) must also be \(\frac{1}{4}\)
How do we do that?
FOr the last part.
how do you do what?
Make the expansion evaluated at 2 = 1/4. If I plug it in, I get like some crazy fraction. How do you make the sum = 1/4
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