$$(x-2y+1)\text dx+(4x-3y-6)\text dy=0$$

$$\frac{\text dy}{\text dx}=\frac{2y-x-1}{4x-3y-6}$$

Question

$$(x-2y+1)\text dx+(4x-3y-6)\text dy=0$$

$$\frac{\text dy}{\text dx}=\frac{2y-x-1}{4x-3y-6}$$

unklerhaukus · Answer

This

unklerhaukus · Answer

http://www.wolframalpha.com/input/?i=f%27+%3D+%282y-x-1%29%2F%284x%E2%88%923y%E2%88%926%29

unklerhaukus · Answer

i have clearly mad aan error

unklerhaukus · Answer

error(s)

sasogeek · Answer

differentiate implicitly? are you asking for it to be checked for you or... i'm not sure what the question is...

unklerhaukus · Answer

there is mistakes in my working because wolfram 's solution is different to mine, can you what i have done wrong

sasogeek · Answer

what was your solution?

unklerhaukus · Answer

it is in pdf 9.pdf, up the page

sasogeek · Answer

ohhh i see, so the question is what you put in the wolfram link and your answer is what's in the pdf link... right?

unklerhaukus · Answer

yes, the question is also in the blue question box at the top of the page

sasogeek · Answer

i'm not sure what we're supposed to do here... are we supposed to solve to the second derivative?

sasogeek · Answer

or we're supposed to integrate?

unklerhaukus · Answer

there is not second derivative,
the question has a form of the first derivative of y with respect to x,
solve the differential equation. ie find an expression for y(x) that does not include derivatives

sasogeek · Answer

sorry but I can't do this integration, i'll see if I can get you some help with @ash2326

ash2326 · Answer

This is a differential equation, I've to check it

sasogeek · Answer

well i thought anti-derivatives were the same as integration... right? from dy/dx to y(x) = integration and from y(x) to dy/dx=differentiation.... ? :|

ash2326 · Answer

Yeah you're right but we have to make some modifications before we can integrate to find y. @UnkleRhaukus jusr wait for some time

unklerhaukus · Answer

ok ill wait

ash2326 · Answer

@UnkleRhaukus Sorry I forgot this form. @lalaly might be able to help you

anonymous · Answer

@UnkleRhaukus, You made a very silly mistake. You wrote dX/dY instead of dY/dX While substituting x=X+h y=Y+k

unklerhaukus · Answer

i did too, thanks @shivam_bhalla.

anonymous · Answer

Hope you are getting the answer now :)

unklerhaukus · Answer

that only changed two terms , that mistake didn't carry through vary far and hasn't changed my result