atomic weight of two element (a) and (b) are 32 and 16 respectively they combine to give two gases ab2 and ab4 and the mixture is found to have a vapour density of 38.4 the number of moles of ab2 in 50 moles of the mixture is ??
Ok. The very first step is to realize that for gases, we can approximate the atomic weight to the density.
Everything else, I completely forget.
molar mass = 2* vapour density
options are 10 20 30 40
the answer is 30
what is ab2, and ab4?
a is an element and b is another element ab2 is its formula
I don't think I can help you, or maybe i just don't know what you are talking about.. Sorry :(
Wait, I might have it. Give me a sec.
ok
ab2 and ab4 molar mass of ab2=64 molar mass of ab4=96
Sulfur and Oxygen
x+y=50 , where x is the amount in moles of ab2, and y is the amount in moles of ab4
yes it is sulphur and oxygen
Then, 64y=96x
Simplify that by dividing by 32 2y=3x
x+y=50 then, 2x+2y=100, or, 2x+3x=100, so, x=20, and y=30
No, I got it all wrong. Give me a second.
(64*c+92*d)/(c+d)=76.8 c+d=50 I thiiink that should be right, although I'm not sure.
you'll want to solve for d, I think.
yes
i did nt understand that step (64*c+92*d)/(c+d)=76.8
now i understood plzz go on with ur answer
Ok. I think it's because I got my equations wrong again.
Say that c:d= number of ab2 molecules: number of ab4 molecules.
ok
Then, 64c+96d=2*38.4 c+d=1, because the concentration of all of the molecules must be 1.
ok
Ok, I might make a lot of mistakes. :S
32d=76.8-64 d=(12.8)/32 c=1-(12.8/32) now, find c*50
i did nt understand
Set c to the concentration of ab2 Set d to the concentration of ab4 Then, c+d must be 1, because the solution is completely made up of ab2 and ab4. Now, 64c+96d=2*38.4, solve for c, and d. c and d are concentrations, not actual values, so we must multiply c*50 to get our answer.
Took me long enough, but I finally have it :D
ha...haaa thanzzzz
You got it? :)
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