What is the rank of a matrix?
THe dimension of column space A
In simple terms it's asking you how many pivot points are in the matrix.
When you try to find the Column A you reduce to echelon form the matrix and find the pivot columns and those pivot columns make up Col A.
Rank of a matrix is an integer \(n\ge 1 \) such that there is at least one minor of order n which is not singular and every minor greater than \( n \) is singular.
Okay, how would you use this to determine whether a linear system with the given augmented matrix has a unique solution infinitly many solutions or no solutions?
Well if you have a square matrix if the rank is equal to n then you have a unique solution.
By using Rouché–Capelli theorem. http://en.wikipedia.org/wiki/Rouch%C3%A9%E2%80%93Capelli_theorem
Never heard of that theorem weird.
In simple words. You have a matrix A mXn . The matrix is unique if the Rank A=n The matrix is infinity if the Rank A<n For no solution you need more information.
Can you give me more examples!
M= 3 -2 0 1 | 1 1 2 -3 1 |-1 2 4 -6 2 | 0
You are trying to find the Rank M?
Or see if it has a unique or infinite solutions?
Yes
to see whether the linear system with the given augmented matrix has a unique solution infinitly many solutions or no solutions
Well you don't really need to know rank in order to know the solution. Do you know how to reduce it to echelon form?
yeah, but i need to know how to do it using the rank method so i know how to use it in general...
Well the answer is no solution but you can't know that with simply using rank.
okay, i see, thanks
http://en.wikipedia.org/wiki/Rouch%C3%A9%E2%80%93Capelli_theorem see you can know if there is a unique solution or infinite but you can't know if there is no solution.
if your teacher told you that you can know if there is no solution by knowing the rank of the matrix I suggest you challenge him/her =)
lol, will do!
Make sure you have your best troll face on when you do.
Actually you can know, if a system is inconsistent (i.e., no solution exists) via rank of the coefficient matrices.
I guess you can but like I said before I see no advantage in using Rank to know if an augmented matrix has a solution or not. Seems like a waste of work.
Like for your example I can tell that there is no solution because the second row is a scalar multiple of the third and if you row reduce that you get a zero row for the matrix that equals a value which means no solution. Again I don't know the Rank and doing so will require more work,
you said something else before and this is a very useful tool.
@SockPuppet WOW! something just clicked in my head!!!
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