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Mathematics 18 Online
OpenStudy (anonymous):

Trigonometry question!!

OpenStudy (anonymous):

Which expression can be used to find the distance between the points B and C of the entrance?

OpenStudy (anonymous):

What expression*

OpenStudy (anonymous):

\[\tan(65)=\frac{BD}{15}\implies BD=15\tan(65)\] is a start

OpenStudy (anonymous):

im assuming the arrow means you simplified

OpenStudy (anonymous):

solved for \(BD\) i did not compute the number. we still need \(DC\)

OpenStudy (anonymous):

\[\tan(25)=\frac{15}{DC}\implies DC=\frac{15}{\tan(25)}\] and them together to get your answer

OpenStudy (anonymous):

since \(BD+DC=BC\)

OpenStudy (anonymous):

How would I enter the trig functions into my calculator to compute them?

OpenStudy (anonymous):

choice 1

OpenStudy (anonymous):

choice 2

OpenStudy (anonymous):

i can't read that

OpenStudy (anonymous):

Top left corner of your screen :p

OpenStudy (anonymous):

3 & 4

OpenStudy (anonymous):

\[15\tan(65)+\frac{15}{\tan(25)}\] is the answer i believe can't read the choices

OpenStudy (anonymous):

none of the choices had Tan in them. They all contained Cot or Sec

OpenStudy (anonymous):

then i guess we have to switch them \[\cot(25)=\frac{DC}{15}\implies DC=15\cot(25)\]

OpenStudy (anonymous):

since you don't have either hypotenuse you cannot use secant

OpenStudy (anonymous):

\[\cot(65)=\frac{15}{BC}\implies BD=\frac{15}{\cot(65)}\]

OpenStudy (anonymous):

So 15Cot(25) + 15/Cot(65)?

OpenStudy (anonymous):

yes if that is a choice, i would pick that one

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