Please find my question attached.

Question

anonymous · Answer

attachment

anonymous · Answer

hmm which of the figure is your question?

anonymous · Answer

10

anonymous · Answer

d is half of 88 I guess... and c is (180-88)/2

anonymous · Answer

http://en.wikipedia.org/wiki/Inscribed_angle_theorem#Theorem

anonymous · Answer

I thought 88 too, but it is not correct.

callisto · Answer

Yes...
d = 88/2 = 44 ( angle at centre, twice angle at circumference)
OA = OB (radii)
=> triangle OAB = isos. triangle.
angle A = angle B ( base angle, isos. triangle)
            = (180 - 88) /2   ( angle sum of triangle)

callisto · Answer

@Hollywood_chrissy    @serychj typed ''half of 88 '' ... = 88/2 :S

anonymous · Answer

huh?

callisto · Answer

Hmm.. what do you mean?

anonymous · Answer

half of 88 is 44 and that is correct.

anonymous · Answer

@Callisto what you described in your post was the arrow theorem right?

callisto · Answer

http://www.benjamin-mills.com/maths/Year11/circle-theorems-proof.pdf See page 2 ... the bottom...

anonymous · Answer

Yeah that is what my teacher called the arrow theorem. But forgive me, what I posted does not look like that.

anonymous · Answer

Angles in the segment, on page 3

callisto · Answer

Nope... angles in the same segment => both angles are formed on the circumference,

callisto · Answer

|dw:1336486723926:dw|
x = y

callisto · Answer

|dw:1336486778505:dw|
angle x is formed at the centre.
x = 2y ( angle at centre, twice angle at circumference)