Question

integrate 1/(e^2)x

Answer 1

Is this correct?\[\int\limits {x \over e^2} \;\;dx\]

Answer 2

no i mean \[\int\limits_{?}^{?} 1/(e^2)x\]

Answer 3

\[\int\limits {1 \over {xe^2}} \;\;dx?\]

Answer 4

yeah that

Answer 5

Then you can integrate as follows\[\int\limits\limits {1 \over {xe^2}} \;\;dx ={1 \over e^2}\cdot \int\limits {1 \over x} \;\;dx\]\[={1 \over e^2} \cdot \ln(|x|) +C\]

Answer 6

why is it

Answer 7

Only because if \(x\leq0\), then \(\ln(x)\) is undefined. So by doing that we can restrict the domain.

Answer 8

ahhhh ok cool thanks!