Question

Estimate the square root to the nearest integer.

Find two integers that make the equation y^2 = 25 true.

Answer 1

A. 5, -5
B. 5, 0.5
C. \[-\sqrt{5}, \sqrt{5}\]
D. 5, 25

Answer 2

For this one, just try some values. Does \(5^2=25\)? What about \((-5)^2\)?

Answer 3

See, there are always two square roots for any number.
One is its real square root and the second one is its additive inverse.

:D

Answer 4

so the additive inverse is not a real root? Is it a false root?

Answer 5

@FoolForMath Real not as in real number, I mean as its positive square root.

Answer 6

@ParthKohli If the roots are complex, the additive inverse is not necessarily the second root.

Answer 7

i think it was D right

Answer 8

What is \(25^2\)?

Answer 9

625

Answer 10

So would 25 satisfy the equation?

Answer 11

@KingGeorge I did mention that. See it above.

Answer 12

Hint, one is a positive and one is a negative.

Answer 13

Okay, so you mean that -5 is not real?

Answer 14

so @ParthKohli it was A

Answer 15

No, no, no. I mean that if it has a real square root, then the other square root would be its additive inverse.

Answer 16

It is @ZhangYan

Answer 17

@ZhangYan: Yes it is A, I think you will find this interesting \[ \large \sqrt[n]{a^n} = a \text{ if $n$ is odd } \]\[ \large \sqrt[n]{a^n} = |a| \text{ if $n$ is even } \]

Answer 18

oh that make sence thanks ffm and parthkohli

Answer 19

Glad to help :)