Question

Which of these sets of numbers contains no irrational numbers?

Answer 1

A. \[-\sqrt{5}, -\sqrt{196}, -8.15\]

B. \[-\sqrt{144}, \sqrt{49}, 6.6\]

C. \[-2, 3/8, \sqrt{10}, -0.6868\]

D. \[-1, 5/6, \sqrt{11}\]

Answer 2

\[\sqrt5, \ \sqrt{10}, \ \sqrt{11}\] are irrational numbers :|

Answer 3

Do you know what is an irrational number?

Answer 4

no...

Answer 5

Okay, an irrational number is a number that can't be expressed in p/q form where p and q are integers and q is not zero.

Answer 6

They are not 'square' number..
let say y is a square number => y = x^2

Answer 7

Now, it can be proved very easily that every surd is irrational or when you multiple anything with a surd the result is irrational.

Answer 8

i am confusing right now....

Answer 9

sorry dinner time here :( I will be back!

Answer 10

surd => a number or quantity that cannot be expressed as the ratio of two integers
For example, for \[\sqrt{2}\], you cannot further simplify it.
Got it?

Answer 11

yeah little bit callisto

Answer 12

for \[\sqrt4\]

\[\sqrt4= \sqrt{2\times 2}= \sqrt{2^2} = 2\]
So, it's not a surd, i think

Answer 13

oh ok i get it so that is no irrational numbers

Answer 14

\[\sqrt4\] is not a irrational number.

Answer 15

ok, it was B

Answer 16

Now the first 20 square numbers are
1, 4, 9 ,16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400
If you see \[\sqrt{x}\] , where x is NOT one of the above numbers, then \[\sqrt{x}\] is an irrational number.

Answer 17

Yes~

Answer 18

ok thanks your informations realy helps :)