Question

solve the equation. (Use n as an integer constant.)

3 cot^2(x) − 1 = 0

x = (smaller value)
x = (larger value)

Answer 1

\[3 \cot^2 x-1=0\]
Add 1 to both the sides
\[3 \cot^2 x=1\]
Divide by 3 both the sides
\[3 \cot^2 x=1\]
We get
\[\cot^2 x=1/3\]
Take root both the sides
\[\cot x=\pm\frac{1}{\sqrt 3}\]
Do you understand till here

Answer 2

so far i do, yes.

Answer 3

so but this not is the end of calcules !!!

Answer 4

now tell me for what value of x, cot x is \(\frac{1}{\sqrt 3}\) ??

Answer 5

cotx=sqrt3 /3

Answer 6

so than x equal what degree ?

Answer 7

do you know the table of sin,cos,tan,cot for degree 30,45,60 ?

Answer 8

I am a little familiar with them

Answer 9

I think i am supposed to be adding 2pi or something.

Answer 10

my book has an example of another question and its final two answers look like, x=(pi/6)+npi and x =(5pi/6) +npi

Answer 11

@mirandaqt are you here?

Answer 12

yes

Answer 13

We had found
\[\cot x= \pm \frac{1}{\sqrt 3}\]
We know tan x= 1/ cotx
so
\[\tan x= \pm \sqrt 3\]
Now tell for what value of x is tan x= \(\sqrt 3 \)

Answer 14

i get 60

Answer 15

yes... 60 degrees.. now, also, going from @ash2326 last post, what other angle gives a tangent of -sqrt3 ?

Answer 16

-60. but this part is confusing me. my book has an example of another question and its final two answers look like, x=(pi/6)+npi and x =(5pi/6) +npi

Answer 17

give the positive angle that's coterminal with -60 degrees.