Question

9 An aqueous solution was prepared containing 1.0mol of AgNO3 and 1.0mol of FeSO4 in 1.00 dm
3
of water. When equilibrium was established, there was 0.44mol of Ag
+
(aq) in the mixture.
Ag
+
(aq) + Fe
2+
(aq) Ag(s) + Fe
3+
(aq)
What is the numerical value of Kc?
A 0.35 B 0.62 C 1.62 D 2.89

Answer 1

1 mole of AgNO3 gives 1 mole of Ag+
1 mole of FeSO4 gives 1 mole of Fe2+

Ag + (aq) + Fe 2+ (aq) --> Ag(s) + Fe 3+ (aq)
inital 1 1
reacts/rpoduce -x -x +x +x
in equilbrium 1-x 1-x x x
1-x=0.44
x=0.56

Kc=[ Fe 3+ (aq) ]/[ Ag + (aq) ]*[ Fe 2+ (aq) ]
......
Kc=x*V/(1-x)^2
Kc=0.56*1/0.44^2
Kc=2.89

Answer 2

thx :)