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MIT 8.01 Physics I Classical Mechanics, Fall 1999 19 Online
OpenStudy (anonymous):

Suppose we are told that the acceleration a of a particle moving with uniform speed v in a circle of radius r is proportional to some power of r, say rn, and some power of v, say vm. How can we determine the values of n and m?

OpenStudy (anonymous):

by dimensional analysis..

OpenStudy (anonymous):

Acceleration is measured in m/s^2...so we need to get these units out of v^mr^n. Velocity is measured in m/s and r=distance is measure in meters. The only way to get seconds^2 out of this is if m=2. Now our units become (m^2/s^2)r^n. We need to get rid of one power of our distance unit. Thus n=-1. This gives us the correct dimensions for acceleration (m/s^2).

OpenStudy (anonymous):

uniform velocity means the paticle only centripital acceleration \[mv ^{2}/r=k m(v ^{^{n/2}})^{2}/r ^{m}\] on copmring. n=2,m=-1

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