Question

apply the Rational Root Theorem to f(x)=2x^4+15x^3+26x^2-5x-6

Answer 1

\[2 x^4+15 x^3+26 x^2-5 x-6=(x+3) (2 x-1) \left(x^2+5 x+2\right) \]

Answer 2

how can i use that to find possible rational roots?

Answer 3

Set each factor on the RHS and solve for x.

Answer 4

RHS?

Answer 5

RHS means is an abbreviation for "right hand side" LHS is short for "Left hand side"

Answer 6

If x+3 is zero, then x = -3. Evaluate the problem expression with x = -3 and the result should be zero.

Answer 7

so the answer is -3, 1/2, and x = -0.2*x^2-0.4?

Answer 8

The solution to \[x^2+5 x+2=0\]is\[\left\{x=\frac{1}{2} \left(-5-\sqrt{17}\right),x=\frac{1}{2} \left(-5+\sqrt{17}\right)\right\} \]You can use the binomial theorem to solve it.

Answer 9

The first two solutions, -3 and 1/2 are correct.