I'll ask again later, I give up for now.
rearrange it as \(2x^3 - 18x - 3x^2 + 27\) that give you ideas?
factor out 2x from \(2x^3 - 18x\) then factor out 3 from \(3x^2 + 27\)
that's 2x^3 remember?
haha ok :))
uhh seems i did a mistype there as well...it's factor out -3 from -3x^2 + 27..sorry...so what will you get when you factor out -3?
no no...it's \[2x(x^2 - 9) -3(x^2 - 9)\] it would be \((x^2 - 9)^2\) if it wer multiplication. Here you just factor out \((x^2 - 9)\)
we'll get there..
and i thought you were asking to "factor" how come now it's orderedpairs?
i see...well anyways you factor out \(x^2 - 9\) since it's common to both terms what do you get?
it seems you are dividing it...you are half correct but factoring is NOT dividing...you stil need the x^2 - 9 \[(x^2 - 9)(2x - 3)\] there's your "ordered pair" ^_^
oh wait..x^2 - 9 is a difference of two squares it can still be simplified
well you are half correct but you cannot just get rid of the one you factored out...
it seems you have a misconception of the word "factoring". First of all, factoring is NOT dividing. dividing gets rid of something. Factoring comes from the word "factor" which means terms that are multiplied. So factoring is not merely dividing..it is expressing a certain term as a product of two terms. for example, \(2x^3 - 18x\) dividing by 2x it is \(x^2 - 9\) BUT FACTORING OUT 2x means \(2x(x^2-9)\). factoring means expressing \(2x^3 - 18x\) as a product of \(2x\) and \((x^2 - 9)\) got it now?
Join our real-time social learning platform and learn together with your friends!