Question

"solving exponential equations and inequalities"
-solve each equation-
((1/2))^(x-3)=16^(3x+1)
help PLEASE

Answer 1

Rewrite the two sides with the same base.

Answer 2

\[\frac{1}{2}^{x-3}=(2^{-1})^{x-3}=2^{-x+3}\]

Answer 3

\[16^{3x+1}=(2^4)^{3x+1}=2^{12x+4}\]

Answer 4

thank you :)

Answer 5

wait then what will x equalt to?

Answer 6

If the bases are the same and the expressions are equal then the exponents must be equal.

Answer 7

Set them equal and solve the resulting equation.