Another area between two curves question...

Find the area bounded by the curves $x = y^2 - 2$ and $x = e^y$ and the lines y = 1 and y = -1

Do i use dy here??

Question

Another area between two curves question...

Find the area bounded by the curves $x = y^2 - 2$ and $x = e^y$ and the lines y = 1 and y = -1

Do i use dy here??

kinggeorge · Answer

I'm thinking dy would probably be a good idea.

lgbasallote · Answer

so is the formula $$\large \int_{-1}^{1} (y^2 - 2 - e^y) dy?$$

kinggeorge · Answer

$e^y>y^2-2$ for your interval, so I would do $$\large \int\limits_{-1}^{1} ( e^y-(y^2-2)) dy$$

lgbasallote · Answer

but in the graph in my book...it shows y^2 - 2 is on the left side...isnt the left side supposed to be where i start? or the right?

kinggeorge · Answer

I didn't think there was a specific side to start on. Rather, whichever one is greater.

lgbasallote · Answer

how do i know which is greater? in the dx it was upper graph minus lower graph

kinggeorge · Answer

Just graph it as if it's in terms of x and not y. Whichever one is higher on that gra[h will also be higher for y.

kinggeorge · Answer

I've got a number theory exam to head off to now, so I'll be gone for a while. Good luck with this question.

lgbasallote · Answer

okay thanks :D