is (0.01) 11, (0.01) 12, (0.01) 13, ... A valid probability distributions for a discrete random variable?
Discrete random variable means you can list all of the possibilities. If you add up all of the probabilities, they should give 1. Simplest example ever: Coin flip; the possibilities are: Heads (.5) Fails (.5) .5 +.5 = 1 So that is a valid distribution.
okay so it has to = 1 got that,... but if you take the (0.01)11 you get 0.11, (0.01)12 you get 0.12.. you have to add them up in order to get one well 13 as lil ................ behind it so i dont know how many im suposed to add after it could go on forever and go past 1.
Really? It only lists the probabilities for 11, 12, and 13 and then has ellipses? That is dumb...
duh...........
lil things like that got me confused
But you're also doing something wrong. The probabilities for all of the variables need to add up to 1. Not the product of the probablity and the variable. Look at my heads/tails example again. I didn't multiply .5 by heads. That doesn't even make sense.
I just knew that my possibilities had probability .5 and .5, I added these up and got 1. No multiplying involved at all =)
I didnt multiply anything. i added
i said nothing about multiplying
"but if you take the (0.01)11 you get 0.11, (0.01)12 you get 0.12" It really looks like you're multiplying there.
How did you get 0.11 if not by multiplying?
ohh see ya got to be specific,.. but thats the thing... its (0.01)11, < which is multiplying THEN you take that answer an add it to the 0.12 which i got from * (0.01)12,...
cant just add them two together when its telling me to multiply then take the sum of that and ad it to the next sum i get.
That sure looks like multiplication, doesn't it? It's not. It's listing the possibilities and the probability for each possibility next to it in parenthesis.
i swear,. i give up. lol
wait that problem copied an pasted wrong lol .. . heres the real problem,. (0.01)*1^1,(0.01)*1^2,(0.01)*1^3....
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