3x²+x+4=0 Help Please !
By using the quadratic formula, you will be able to find x.
\(\large \frac{-b \pm \sqrt{b^2 -4ac}}{2a}\)
it has no roots
In this case, a = 3 b = 1 c = 4 Plug it in the formula \(\huge \frac{-(1) \pm \sqrt{(1)^2-4(3)(4)}}{2(3)}\) Then you'll find out that the discriminant is a negative, hence it has no roots; it also means that the parabola doesn't lay on the x-axis.
you will end up with 1/12 (-i+sqrt(47)-6 i x) (i+sqrt(47)+6 i x) as your factored form
\[1/12 (-i+\sqrt(47)-6 i x) (i+\sqrt(47)+6 i x)\]
how did yu get that ?
using the quadratic formula just like zepp said you get a negative under the radical
ooh i get it ! thanks so much
to you both !
|dw:1336529470840:dw| if you look at the graph, notice that the function does not cross the x axis you will have 2 complex solutions when you use the quadratic formula, there will be a negative number under the square root sign
\[\Delta = b^2 - 4 a c= 1^2 - 4(3)c= -47 = i^2 47\\ \sqrt \Delta = \pm i \sqrt {47}\\ x= \frac { -1 \pm i \sqrt {47}} { 6} \]
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