Find all 3 radii.
|dw:1336530427402:dw| AB=8 BC=13 AC=11
The line AB is mad up of the radius of A and the radius of B. Likewise for BC and AC. So\[AB=r _{A}+r _{B}\]\[BC=r _{B}+r _{C}\]\[AC=r _{A}+r _{C}\]
And then?
(The hint was that it's a work around problem)
You have three equations and three unknowns. Do you know how to solve a system like this?
nope
I'll understand if you just show all the work ;)
Okay. Let's rearrange the 3rd equation\[r _{C}=11-r _{A}\]Let's plug this into the second equation to get\[r _{B}+(11-r _{A})=13\]\[r _{B}-r _{A}=2\] Now you can use this equation and the first equation to solve for r_B and r_A. \[r _{A}+r _{B }=8\]
Give me the final equation for the answer and the answer, please.
You know\[r _{A}+r _{B}=8\]\[r _{B}-r _{A}=2\]If you add the 2 equations together you get\[2r _{B}=10\]You should be able to handle it from here.
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