Question

How do I prove this identity: tanx + 1/tanx = 1/sinxcosx? o.O

Answer 1

\[tanx + 1\div tanx = 1 \div sinxcosx\]

Answer 2

Try it. D;

Answer 3

I got

Answer 4

@milliex51 , yay!

Answer 5

\[sinx/cosx + 1/(sinx/cosx)\]
\[1 x \cos ^{2}x/\sin ^{2}x = 1/sinxcosx\]

Answer 6

and I'm stuck.. D:

Answer 7

which one is the main problem? Lol

Answer 8

what do you mean?

Answer 9

You wrote two things above

Answer 10

oh those are my steps..

Answer 11

WAIT. i did this same question some days ago!
are you doing CIE by any chance?

Answer 12

what's CIE? o.o

Answer 13

Cambridge Intl' Examinations.

Answer 14

That question was in my exam yesterday! OMG! im shocked.

Answer 15

oh noooo

Answer 16

LOL, sorry never did CIE

Answer 17

tanx + 1/tanx = 1/sinxcosx?
\[\frac{\sin x}{\cos x} + \frac{cosx}{\sin x}\]Solve. :)

Answer 18

is it uh... sin^2x / cos^2x...?

Answer 19

No, we will take "cosx sinx" as Lcm.

\[\frac{\sin x(sinx) + cosx(\cos x)}{\cos x \sin x}\]

Answer 20

so sin^2x + cos^2x / cosxsinx... but how? D:

Answer 21

Add,

1/6 + 1/7

Answer 22

oh it's 7/42 + 6/42?

Answer 23

Yes but how you got it?
you took LCM right? and then multiplied it by numerator..

Answer 24

We will do the same thing there.

Answer 25

yes! thank you! :)

Answer 26

Welcome.