Question

A light rope is fixed at one end of a wooden clamp on the ground passes over a branch and hangs on the other side. It makes an angle 30 degrees with the ground. A man weighing 60 kg wants to climb up the rope. The wooden clamp can come out of the ground if an upward force greater than 360N is applied. Find the max ace in the upward direction with which the man can climb safely. Neglect friction at the tree branch. Take g=10m/s^2

Answer 1

sol..Let T be the tension.
Upward force is Tsin30=t/2=360N
this is what i dont understand dont u take normal force into account???

Answer 2

the force would be the
upward force-downward force...?

Answer 3

I wrote the above from the solution/
T+N-mg=360 i think this is what it should be

Answer 4

T sin30 =360N
and then T-360= Force
and then Force=ma

am i missing something?

Answer 5

sorry that's 600-T=force

Answer 6

this is what iam asking
why is Tsin30=360
and not
T+Normal force-mg=360 ?

Answer 7

Normal force?

Answer 8

im talking about the clamp

Answer 9

oh, well actually as you can see in your diagram, the upward tension in the rope comes out to be the same if you take it from the clamp or if you take it from where the person is hanging down...the TENSION in the rope means the same thing from either side of it you take....

Answer 10

why is Tsin30=360(the total upward force)
and not
T+Normal force-mg=360 ?
with clamp as system

Answer 11

The tension and normal force are the same thing.