How do i solve the equation (6t+4)^2=3 ?
square root both sides...tried that?
(6t+4)^2=3 (6t+4)(6t+4)=3
i squared but answer has a +- square root fraction
square root both sides \[6t + 4 = \pm \sqrt 3\] subtract both sides by 4
PEMDAS good ol' 6th grade. 1) Parentheses: they're as simplified as they can be 2) Exponent: you can do this (6t+4) * (6t+4) =3 3) Multiply: 36t^2+48t +16 = 3 got the rest from here?
answer should be\[\left\{ \pm \sqrt{3-4}\right\}/6\]
That's not correct. The correct answer is \[(-4\pm \sqrt{3})/6\]You can get this using the quadratic formula of \[(-b \pm \sqrt{b^{2}-4ac})/2a\]
your answer is the one i see here but its the opposite way -4 is after square root 3 does it make a difference or is the same thing.
As long as -4 is outside the root, it should be the same.
ok ty
how do i end up with a square root of 3 and denominator of 6t?
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