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Mathematics 16 Online
OpenStudy (anonymous):

In △PQR, what is the length of QR ?

OpenStudy (anonymous):

OpenStudy (anonymous):

Once again you can use cosine. \[\cos 45 = \frac{QR}{42}\] \[21 \sqrt{2} = 29.698484809834996024835463208404 \]

OpenStudy (anonymous):

Thanks SO much, you're helping me more than you know. is it ok if we do a few more? i hate to be a bother?

OpenStudy (anonymous):

I've got a bit of time, fire some away.

OpenStudy (anonymous):

In △JKL, what is the length of KL?

OpenStudy (anonymous):

Use tan, which is Opposite/Adjacent \[\tan60=\frac{KL}{33}\] \[33\sqrt{3}=57.157676649772950686405729269694\]

OpenStudy (anonymous):

In △DEF, what is the length of ?

OpenStudy (anonymous):

FE or FD?

OpenStudy (anonymous):

FD, sorry about that

OpenStudy (anonymous):

Use sine. \[\sin60 = \frac{45}{FD}\] \[30\sqrt3=51.961524227066318805823390245176\]

OpenStudy (anonymous):

THANKS, do you think you can take anymore?

OpenStudy (anonymous):

Try one of them out, they aren't very hard if you know your sine, cosines, and tangents.

OpenStudy (anonymous):

In the figure below, the length of GE is 97sqrt 3 units and the length of BG is 149 units. What is the length of AC?

OpenStudy (anonymous):

Determine AG. \[\tan 60 = \frac{97\sqrt{3}}{AG}\] \[AG=97\] Subtract to find BA. \[149-97=52\] Then use cosine to find AC. \[\cos 45=\frac{52}{AC}\] \[AC=52\sqrt{2}\]

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