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derivative of cos^2(sin(x))
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what's the first step?
use chain rule
i know chain, but...
i think im suppose to use law of logarithms to bring the square down
why do you want to bring down the square take f(x)=sinx and g=cos^2(f) ow find g'
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-2cos(sinx) * sin(sinx)
?
\[ f(x)= \cos^2(\sin x)\\ f'(x)=-2\cos(\sin x)\cdot\sin(\sin x)\cdot \cos x \]
why that last cosx?
You have to use the chain rule twice. You have basically f(x)=x^2, g(x)=cos(x), h(x)=sin(x), and you have f(g(h(x))), so apply chain rule twice.
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