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Find the largest factor of 2520 that is not divisible by 6.
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315
how do u calculate it ?
well the prime factorization of 2520 is 2^3 x 3^2 x 5 x 7 any factor of 2520 that is divisible by 6 contains at least one 2 and at least one 3 in its prime factorization. so remove factors so that no 2's remain or no 3's remain if we remove all the 3s, we divide the number by 3^2 = 9. but if we remove all the 2s, we divide the number by 2^3 = 8 since 8 is less than 9 the last factor 2520/8 = 315
How did i calculate .... 2 x 2 x2 x 3 x 3 x5 x 7 the remainder value at first occurance of 3 is 315 which is not divisible by 6 first 3 occurance of 2 ... remainder values are divisible by 6 does it make sense
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