Question

find \[ {dy \over dx}xsin2x\]

Answer 1

@.Sam.

Answer 2

Differentiate xsin2x?

Answer 3

use chain rule

Answer 4

yeh

Answer 5

you also need the product rule
f(uv) = uv' + vu'
let u = x and v = sin2x

Answer 6

(uv)'=u'v+uv'
here u=x and v=sin2x

Answer 7

dy/dx=x(cos(2x)(2))+(sin2x)

Answer 8

\[x \ \frac{d}{dx}\sin(2x)+ \sin(2x) \ \frac{d}{dx}x\]

Answer 9

\[(x )\ 2 \cos(2x)+\sin(2x)\]

Answer 10

@Diyadiya I thought we should n't give away answers

Answer 11

huh ? @vamgadu
not answers ..*Final answer