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x, y, z is a geometric sequence with common ratio r and \[x \neq y\] . if x, 2y, 3z is an arithmetic sequence, find r.
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is that the whole question?
yes... what's r in the geometric sequence..
y/x ?
I think \[r=\lim_{n \rightarrow \infty}x _{n}/y _{n}\]
so, 1/3?
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yeah.. @UnkleRhaukus .... good one...
\[3\approx\infty\]
are you sure this is the answer?
no
i don't know, but i see it this way: y=rx,z=r^2x so: 2y-x=q or 2rx-x=q also: 3r^2x-x=2q substituting value for q in the 2º equation: 3r^2x-x=4rx-2x or: r^2-4/3r-1=0 and solve for r
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@dpaInc
is the answer 1/3 in question?
no
i have no idea how he got 1/3
y=xr, z=yr=xr^2 3z - 2y = 2y - x
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substitute y an z into that last equation..
oh, right, i made a mistake....
you were getting it though....
...
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