Question

the positions of three particles are as follows


x=3t+2.5t^2

x=5/2t(2+t)

x=6 + 3t-2.5t^2

relative motion is uniform between (i) and (ii) (ii) and (iii) (i) and (iii) all of these

Answer 1

i and iii?

Answer 2

inkyvoyd why did u block me..

Answer 3

the answer is a

Answer 4

I didn't block you 0.o

Answer 5

ohhh sorry>>

Answer 6

x=5/2t(2+t)
is that t under the 5?

Answer 7

no it is 5t/2

Answer 8

did u get the answer inkyvoyd

Answer 9

so, t(5+(5t)/2)=(5t^2)/2+5t

Answer 10

I'd say that it's i and ii because they have the same coefficient for the term of second degree (ax^2)

Answer 11

what u r saying the question is to find the relative motion is uniform in

Answer 12

Well, because the term of the second degree is the same, their velocities are both the same.

Answer 13

the third one also has degree 2

Answer 14

then......

Answer 15

Do you know how to tak the derivative?

Answer 16

yes

Answer 17

Right now the equations we have describe displacement. The derivative of displacement is velocity. The derivative of that is acceleration. relative motion is uniform if they are the same.(the accel)

Answer 18

ok

Answer 19

x=3t+2.5t^2
a=5
x=5/2t(2+t)
a=5
x=6 + 3t-2.5t^2
a=-5

Answer 20

Since i and ii have the same accleration, that is the answer.

Answer 21

thanxxx

Answer 22

next question !!!

Answer 23

Alternative way is to look at it this way
d=vt+(1/2)at^2
compare the a, and if it is the same, then you know they are the same.