Question

three points a b c are on straight line such that ab=ac. a particled moving with uniform acceleration passes a and c with speeds 6m/s and 8m/s respectively. another particle moving with uniform acceleration passes a and b with speeds of 12m/s and 14m/s respectively it t1 and t2 are the times taken by the particle to cross ab t1/t2 is nearly??

Answer 1

omg

Answer 2

what is omg??

Answer 3

oh-my-god lol

Answer 4

why??

Answer 5

Alright. Begin with the equation.
\(d=V_0t+(1/2)at^2\)

Answer 6

ok

Answer 7

\(\frac{2}{a_1}=t_1\)
\(\frac{2}{a_2}=t_2\)

Answer 8

\(\huge \frac{t_1}{t_2}=\frac{a_2}{a_1}\)

Answer 9

did nt understand

Answer 10

2a1=t1
2a2=t2

Answer 11

(8m/s-6m/s)/2=a1

Answer 12

same for a2

Answer 13

ok

Answer 14

hey from where at 2 came....

Answer 15

(14m/s-12m/s)/2=a2

Answer 16

a1 is the accleration of first,
a2 is acceleration of second.

Answer 17

ok

Answer 18

then....

Answer 19

Now, go back to the first equation.

Answer 20

hey wait how this came (14m/s-12m/s)/2=a2 a =v2-v1/time

Answer 21

time is not given

Answer 22

why did u take it as 2???????

Answer 23

Sorry, I forgot time.

Answer 24

my equations in latex should be correct.

Answer 25

Lol, I'm not completely sure how to do the problem. What's the answer?

Answer 26

the answer is 2

Answer 27

three points a b c are on straight line such that ab=ac. a particled moving with uniform acceleration passes a and c with speeds 6m/s and 8m/s respectively. another particle moving with uniform acceleration passes a and b with speeds of 12m/s and 14m/s respectively it t1 and t2 are the times taken by the particle to cross ab t1/t2 is nearly??

Answer 28

The key is "is nearly". we have to approximate the values, and I'm not sure how to do that.

Answer 29

leave it next question.....