a body is thrown vertically up with a speed of 10m/s from the top of a wall of height 3.45m..the height from which another body should be dropped simultaneously such that two bodies reach the ground at the same time is (g=10m/s^2)

Question

inkyvoyd · Answer

One sec, thinking.

anonymous · Answer

ok

inkyvoyd · Answer

Ok, for the first body, we must find the equation.

anonymous · Answer

options are    40m         24.5m        6.9m      20m

inkyvoyd · Answer

For the height with respect to time.

inkyvoyd · Answer

I'm going to cheat here, and use an equation for modelling projectile motion. Can I do that?

anonymous · Answer

i have asked this question 3 times but i did nt understand those if u want take a look i will give the link

anonymous · Answer

http://openstudy.com/study#/updates/4fa76aede4b029e9dc3861f0

anonymous · Answer

view that

anonymous · Answer

ok plzz do it in ur way of modelling projectile motion

inkyvoyd · Answer

wait, I think I can explain dumbcow's method.

anonymous · Answer

ok

inkyvoyd · Answer

d=ut+1/2 at^2 right?
Let's make "up" our positive, and "down"our negative.

anonymous · Answer

ok

inkyvoyd · Answer

We want to know when d=0. Does that make sense?

anonymous · Answer

no

anonymous · Answer

r u there

inkyvoyd · Answer

Ok. You are used to distance being positive for forward, and negative for backward, right?

inkyvoyd · Answer

|dw:1336565700530:dw|
This is what you are used to.

inkyvoyd · Answer

This is what we need to do.|dw:1336565743225:dw|