a car travels in a straight line with vatying velocity given by v={t - t0}m/s for 0<_<_2t0 where t=time and t0= time at which velocity is zero the distance travelled by the car in this interval is?
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OpenStudy (anonymous):
option are t0^2 2t0^2 3/2t0^2 0
OpenStudy (inkyvoyd):
Not sure. Can we go back to the last qusetion?
OpenStudy (anonymous):
the answer is a
OpenStudy (inkyvoyd):
I'm not sure how to answer this question. @dumbcow ?
OpenStudy (anonymous):
i think we have to use vector
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OpenStudy (anonymous):
x= \[x=x0+v0 \times t + at ^{2}/2\]
since
x0 = 0 - there is no any notion on initial position of object
v0 = v(t0)=0 it is given in problem
we get
\[x=at ^{2}/2\]
OpenStudy (anonymous):
let's find
acceleration
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
at=v
=>
a=v/t
v= t-t0
a=(t-t0)/ t
OpenStudy (dumbcow):
i guess i would go with
\[d = \int\limits_{0}^{2t_0}v(t) dt\]
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OpenStudy (anonymous):
Now try to put expression for a and t= 2t0 in
\[x=at ^{2}/2\]
OpenStudy (anonymous):
i get it thanxx to both of u another question plzz view it