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Solve the following: One car left Carville driving toward Beattyville, which is 300 miles away. A second car left Beattyville at the same time, driving toward Carville. If the first and second cars are averaging 55 mph and 65 mph, respectively, in how many hours will they pass each other?

2 hours

3.5 hours

2.5 hours

3 hours

Question

1 points  	Save  
 	
Solve the following: One car left Carville driving toward Beattyville, which is 300 miles away. A second car left Beattyville at the same time, driving toward Carville. If the first and second cars are averaging 55 mph and 65 mph, respectively, in how many hours will they pass each other?
 
		
2 hours
 		
3.5 hours
 		
2.5 hours
 		
3 hours

anonymous · Answer

helpp !

anonymous · Answer

i got 3 hours. and again please ask physics questions in physics department

anonymous · Answer

opss sooooooo  sorry i thought i was in math section sooo sorry

anonymous · Answer

did you solve it? you assume that they travel at same speed so they meet at half path or 150 mi now you use the speed difference and calculate what distance one car travels if he goes 10 mph faster and add to 150 and now you reverse the equation and with that distance you take any car and calculate the time and you should get 3 hrs

anonymous · Answer

RT + RT = D
55x + 65x = 300
120x = 300 
x = 2.5
They will pass each other in 2.5 hours.

anonymous · Answer

i think you are right shonengetsu, i made wrong assumptions