A square is inscribed inside a circle. The square's vertices have coordinates R(0, 4), S(6, 2), T(4, -4), and U(-2, -2). Find the equation of the circle. (x-?)^2+y^2=?
guess we need the center and radius. let me draw a picture. center will be halfway between the diagonal of the square, and radius will be half the length of the diagonal. i am guessing that you can find both of those, but if not let me know
satellite can u help me too please
|dw:1336570391333:dw|
we can use \((0,4)\) and \((4,-4)\) as the two points we need the midpoint and the distance. let me know if you need help finding those
yes please
to find the midpoint, take the average of the coordinates \[(\frac{0+4}{2},\frac{4-4}{2})\] \[(2,0)\] is the center
now for the radius squared, find the square of the distance between \((2,0)\) and \((0,4)\) by pythagoras. it is \[2^2+4^2=4+16=20\] now you have both the center \((2,0)\) and \(r^2=20\) so you can write the equation
Join our real-time social learning platform and learn together with your friends!