Question

plz view this

Answer 1

117 118 plzzz

Answer 2

Sorry, i didn't read question properly
given, u = x,
let v = x - 20%of x = 0.8x
s = 0.9

what can we say from it??
v^2 = u^2 + 2as

Answer 3

is it -2as retardation..

Answer 4

oh ... yes

Answer 5

find the value of x in terms of a!!
quite bg for now!!

Answer 6

0.8x^2=x^2-2*0.9*a

Answer 7

is it

Answer 8

(0.8x)^2 <--- error here

Answer 9

why??

Answer 10

v = x - 20%of x = 0.8x

Answer 11

i think this is complicated we can solve it later plz take a look at 119...

Answer 12

20% = 20/100
1 - 20% = 80% = 80/100 = 0.8

Answer 13

this is easy .... just find the value of x

(1-0.64)x^2 = 2*0.9*a
x = ??

and now put it here

v = u + at <--- find the time then

Answer 14

is it x^2??

Answer 15

yea

Answer 16

yes ... that is what i've been telling you all the time!!!

Answer 17

x=\[\sqrt{5a}\]

Answer 18

is it???

Answer 19

v=u-at is it retardation???

Answer 20

yeah ... put the values of x's of u and v and find the time ... see what you get!!

Answer 21

oh......no...

Answer 22

we can do this after plz do 119

Answer 23

i think we will be able to get that fast

Answer 24

a=−u20/5m

Answer 25

it takes 3 second to go up and 3 second to come down!!

Answer 26

sorry .. it was 2.5s

v = 0, t = 2.5s, a=10

what can you determine from this parameter??

Answer 27

ok in this question there is more than one answer so we have to check each options

Answer 28

we can find u

Answer 29

v=u+at

Answer 30

yes .. find u!!

Answer 31

and u would be at ... 1s after, it is projected ... so it will again be final velocity to find the original velocity.

Answer 32

u=25m/s

Answer 33

so again
v = 25,
t = 1s
a = -10
u = ??

Answer 34

u=35m/s

Answer 35

okay!!


So we have this picture ... and also note that the path is straight up .. rather than parabolic.
It is just for illustration!!