Question

Write balanced nuclear equations for the formation of five elements whose atomic number is between helium (2) and iron (26).

Answer 1

It's about the balanced equations that show the fusion of lighter elements into heavier elements.

Answer 2

He + He -> Be
Be + He -> C
C + Be -> Ne
C + He -> O
O + Be -> Mg
is that what you had in mind?

Answer 3

Thank you :)

Answer 4

is it balanced ?

Answer 5

balanced nuclear equations*

Answer 6

well you should write proton and mass nubers and add them together but that should be allright

Answer 7

is it okay if you can balanced it for me?

Answer 8

ill give you an example:
\[_{4}^{2}He + _{4}^{2}He + n ^{0} \rightarrow _{9}^{4}Be\]

Answer 9

can you give me the site where it shows the balanced equations for this?
because i really need it :/

Answer 10

since i have four more left if thats fine with you..

Answer 11

all you need is periodic table but ill try to find you something on net

Answer 12

ok thanks

Answer 13

here you go:
http://www.docbrown.info/page03/3_54radio08.htm

Answer 14

so i can use :
13/6 C + 4/2 He -----> 16/8 O + 1/0 n ?

Answer 15

yes

Answer 16

What does it mean when it says atomic number between helium (2) and iron (26)?

Answer 17

Pumpkin 890 it means the any element between helium and iron. So He has the atomic number of 2, and Fe has the atomic number of 26. The reason being is that a star cannot build any element beyond iron without succumbing to its size and dying either in a red giant, supernova or hypernova. These catastrophic events are what cause the other elements to be made. All elements in the universe started as hydrogen atoms originally. Lighter elements like Hydrogen and Helium fuse together to form heavier elements.