Question

Quick geometry question....

Answer 1

THIS IS THE DOC with question on it

Answer 2

@FoolForMath or @experimentX , @satellite73 or @Zarkon please try and help me with this..

Answer 3

okay... @FoolForMath do you think u can do it?? I'm time limited;P

Answer 4

cn i help?

Answer 5

yeah you can! everyone can help!

Answer 6

kk whats the Q?

Answer 7

look above in the doc form

Answer 8

k

Answer 9

Okay.
THink about the theorum they have used.
Hint - What angles in the question are equal

Answer 10

angle B is equal to itself .. we can use the reflexive theorem?? but I'm not so sure above the other angles..

Answer 11

is there any corresponding angles here?

Answer 12

No. I dont think it would help.
The lines DE and AC are parallel.
Look at the corressponding angles.

Answer 13

Yes. Precisely.
Angle BDE = Angle BAC
And similarly the other one.
Then by AA rule you prove the triangles similar, and the rest is given :)

Answer 14

ohhh but .... whats the other angles that are corresponding.... so to fill in the proof... how would i do that?

Answer 15

angles BDE = Angle BAC : BY the AA similarity postulate. ?

Answer 16

No.
Angles BDE = Angle BAC ( Since DE parallel to Ac -> Corresponding angles property)
And BED = Angle BCA ( Same reason as above)
^^ These are the blanks.

Answer 17

Ohhhhhh!! i see now... THANKS siddhantsharan!! :) <3 you really hellpeddd

Answer 18

Haha. Anytime :)