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Physics 13 Online
OpenStudy (anonymous):

plz view this

OpenStudy (anonymous):

plz view 108 ??

OpenStudy (anonymous):

First, what is relative motion? Relative motion is motion of object 2 with respect to object 1 Relative velocity(v) of v2 with respect to v1 is v = v2 - v1 Relative velocity(v) of v1 with respect to v2 is v = v1 - v2 To make sure relative motion is uniform you need to make sure the v you are getting should be linearly dependent on t. i.e the t^2 terms of v2 and v1 should cancel out in v and v should be linearly dependent on t for uniform motion t-->time Now try :)

OpenStudy (anonymous):

id nt understand plz can u solve 1st one as example

OpenStudy (experimentx):

what is uniform motion??

OpenStudy (anonymous):

moving with constant velocity

OpenStudy (experimentx):

No ... not exactly!!

OpenStudy (anonymous):

why?

OpenStudy (anonymous):

uniform motion is something moving in a straight line at a consistent speed

OpenStudy (anonymous):

r u talking about relative velocity??

OpenStudy (experimentx):

yes ...

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

plz go on

OpenStudy (experimentx):

what is the condition for two particles to have same velocity with respect to each other?

OpenStudy (anonymous):

if they are in opposite direction or same direction???

OpenStudy (experimentx):

\[ \frac{d}{dt}x_1(t) - \frac{d}{dt}x_2(t) = k \] K is constant!! I think it should be like this!!

OpenStudy (anonymous):

calculus???? i think it is the way

OpenStudy (experimentx):

well ... if you try to see other way ... then it's easier if you can analize the given equation

OpenStudy (anonymous):

derivative of distance is velocity

OpenStudy (experimentx):

Wait ... i think i need to check the definition of uniform motion again!!

OpenStudy (anonymous):

ok

OpenStudy (experimentx):

http://en.wikipedia.org/wiki/Linear_motion "uniform linear motion, with constant velocity or zero acceleration" says \( \frac{d}{dt}x_1(t) - \frac{d}{dt}x_2(t) = k \) <---constant velocity or \( \frac{d^2}{dt^2}x_1(t) - \frac{d^2}{dt^2}x_2(t) = 0 \) <--zero acceleration. Now i think, you can find it!!

OpenStudy (experimentx):

if you know your distance formula ... you don't need this stuff!!

OpenStudy (anonymous):

we have find acceleration using derivative....

OpenStudy (anonymous):

\[\sqrt{x2-x1 +y2-y1}\]

OpenStudy (anonymous):

distance formula

OpenStudy (experimentx):

when two particles have same velocity w.r.t each other?? then they have same acceleration ... Jeez ... what are you trying to do??? look for equations where they have same acceleration ...

OpenStudy (anonymous):

derivative????

OpenStudy (inkyvoyd):

I think that @shivam_bhalla explained it pretty well :S

OpenStudy (experimentx):

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