Please Help =0 Consider the line that passes through the point (-1, 6) and has a slope of -4. Part 1: Write the equation of this line using point-slope form. Part 2: Using your equation from part 1, rewrite this equation in slope-intercept form. Make sure to show all of your work. Part 3: Using your equation from part 2, rewrite this equation in standard form. Make sure to show all of your work.
I made a tutorial on this, you can take a look and try to do part 1 :) Let me know if you understand something there :))
Thank you =)
Now for the part 2 and 3 (Since I didn't put that in my tutorial). By using the point-slope form, you can easily find the slope-intercept form as you can see in my tutorial (By distribution and sending y to one side); And for the standard form (or the general form) you simply set one side to 0 and there you go! :)
but i still dont get it
Which part?
Point-slope form! \[\large y - y_{1} = m(x-x_{1})\]\[m= slope; ~~~~x_{1} ~and~y_{1}: A~point~on~the~function\] Plug the slope and the point in it :)
Your point is (-1, 6), thus, \(x_1\) is -1 and \(y_1\) is 6
ok thank you =)
Np ;)
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