Question

how do you write something in vertex form?

Answer 1

a quadradic equation

Answer 2

in vertex

Answer 3

so if it said y=x^2 +14x+11 in vetex form how would it be solved

Answer 4

thank you

Answer 5

(y = a(x-h)² + k is vertex form)

I'm not sure the example you gave can be put into vertex form

Answer 6

im taking integrated geometry the algebra part "integrated

Answer 7

okay i can do that part, so then what do you do with the answer after completeing the square

Answer 8

hold on...

Answer 9

im not sure i can with this problem

Answer 10

Pretty sure you can't...

Try this one:
y = 3x2 + 2x – 1

Answer 11

Correction: 3x^2 + 2x - 1

Answer 12

k

Answer 13

x=1/3,-1

Answer 14

not the solution...
you want to make it vertex form right?

Answer 15

yes

Answer 16

I got(-1/3, -4/3) using the -(b/2a)

Answer 17

how?

Answer 18

\[y=3x ^{2}+2x-1\] was what redshift gave us. To find the x value of the vertex we use the equation x=- b/2a substituting 2 for b and 3 for a we get - 2/6 or -1/3 Then to get the y value substitute -1/3 for x in the original equation.

Answer 19

please note that is the location of the vertex, it is not the equation in vertex form;

Answer 20

OK..

Given y = 3x^2 + 2x - 1:

-move the -1 out of your way(to the other side)
-factor out a 3 on the right side
-divide both sides by 3
-take the coefficient in front of "x" not "x^2" and divide it by 2 and square it
-add that number to both sides

-make the ( )^2 part by:
-taking the coefficient in front of "x"(not "x^2") and divide it by 2(we'll call it "n")
it will be: (x + n)^2

Then just move stuff around to make vertex form.

Answer 21

I'm not sure how good my explanation is but try it out and check by taking your answer and expanding it again to make the original question.

Answer 22

okay thanks

Answer 23

so after moving the -1 it would be 3x^2+2x=1

Answer 24

y=3(x+1/3)^2-4/3
is this the vertex form?

Answer 25

don't forget the y:

y + 1 = 3x^2 + 2x

Answer 26

@radar: yes

Answer 27

Thanks.

Answer 28

oh, and yes that is in vertex form

Answer 29

what do you mean factor out a 3 on both side

Answer 30

\[3x ^{2}+2x=y+1\]\[3(x ^{2}+(2/3)x)=y+1\] To factor 3 out of both sides:\[x ^{2}+(2/3)(x)=y/3 + 1/3\]

Answer 31

Now continue with the receipe.

Answer 32

haha thank you

Answer 33

Take 1/2 of the x coefficient which is 2/3, so 1/2 would be 1/3 now square the 1/3 getting 1/9 and add it to both sides of the equal sign.

Answer 34

x^2+1/9=y/3 +1/3 ?

Answer 35

\[x ^{2}+(2/3)(x) +1/9=y/3+1/3+1/9\]We now have a perfect square on the left and work to do on the right.\[(x +1/3)^{2}=y/3+1/3+1/9\]
Lets do some clrean up on the right\[(x+1/3)^{2}=y/3+4/9\] subtract the 4/9 from both sides getting:\[(x+1/3)^{2}-4/9=y/3\] Multiply both sides by 3 to isolate y.\[y=3(x+1/3)^{2}-4/3\] There it is as redshift said it would be.

Answer 36

wow! alright.

Answer 37

That is in vertex form, the x value is -1/3 the y -4/3

Answer 38

Thanks so much i cant believe i forgot this from a unit back

Answer 39

You were there, a little review never hurts. Good evening all.

Answer 40

your right about that