Help woud be greatly appreciated, I am in a timed pretest environment and do not understand this...
When grams of Mg 9 (s) reacts with HCl (aq), 2L of H2 gas is formed (at STP). How would the amount of H2 gas produced change if the volume of Mg (aq) double d to 2x grams?
The equation for the reaction is: Mg (s) + 2HCl (aq) → H2 (g) + MgCl2 (aq)

Question

anonymous · Answer

I would assume that double of gas, if i understand what your saying, if 9 grams of Mg produces 2L of H2 the double of grams (18) would produce 4L of H2. 
Explanation: stoichiometry of reacction

anonymous · Answer

@levinelevine That'd what I thought as well, but it was incorrect! Hmmm...

anonymous · Answer

if the amount of HCl is unchanged it would produce the same amount. check ur question cause youre also saying that Mg is aq and stuff like that.

anonymous · Answer

ok
thanks