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Just checking my answer... Find the volume of the solid obtained by rotating the region bounded by \(y = \frac{1}{4} x^2\) and \(y = 5 - x^2\) about the x-axis. I got \(\frac{176\pi}{3}\)
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i got something else again...
youuuu =____=
it's sorta close to yours....
wanna know what I got?
this is washer method right?
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yep...
then whyyyy =_=
uhh phooey i forgot to integrate x^4/16 =_=
\[\frac{868\pi}{13}\]
umm...
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i hope you don't get mad at me.... your first answer is correct...
yep.. you're mad.... cya...
lol :PPPP
seems i combine x^4/16 already haha
i was squaring like this (g-f)^2 and not g^2 - f^2 ... imagine that... :P
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lol =))))
now you are a master....
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