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Why does 6(-5/6)^n converge to zero?
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Because the magnitude of -5/6 is less than one. When two numbers are less than one and repetitively multiplied(like 0.5 to an exponent for instance), they make a smaller and smaller number. Here is the graph: http://www.wolframalpha.com/input/?i=6%28-5%2F6%29%5En
I get that (5/6)^n will get smaller and converge to 0. The (-) must make the series alternating. When (5/6)^n converges to zero, it never actually reaches zero. Would one treat it as a 0 being multiplied by 6 anyway when considering infinite behavior?
Yes because even though it is alternating it is getting closer and closer to the x-axis(zero). So (-5/6)^n converges to 0 and 6*0 = 0
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