Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (vishweshshrimali5):

help with calculus

OpenStudy (vishweshshrimali5):

OpenStudy (anonymous):

Is that a comma or a y' at the end of that first equation?

OpenStudy (vishweshshrimali5):

it is a coma

OpenStudy (anonymous):

So I guess you integrate the first equation, use y(0) = 0 to find the constant, and substitute into the equation to find the answer. Give me a minute to try this

OpenStudy (vishweshshrimali5):

k

OpenStudy (anonymous):

I'm finding it really difficult. There doesn't seem to be a good way to simplify it: http://www.wolframalpha.com/input/?i=%28%28cosy+-+2sinx+-+6%29cosx%29%2F%28%28sinx+%2B+4cosy+%2B+2%29siny%29

OpenStudy (vishweshshrimali5):

so what should we do then........

OpenStudy (anonymous):

Hmm. I'll keep looking at it and I'll let you know if I come up with anything.

OpenStudy (vishweshshrimali5):

ok thanks

OpenStudy (anonymous):

Actually, we're just taking the integral with respect to x right? So I couldn't come up with it myself but wolfram alpha produces this: http://www.wolframalpha.com/input/?i=integral+with+respect+to+x%3A+%28%28cosy+-+2sinx+-+6%29cosx%29%2F%28%28sinx+%2B+4cosy+%2B+2%29siny%29

OpenStudy (anonymous):

So substitute (x,y) = (0,0) for the constant and then substitute Pi/2 into the equation.

OpenStudy (vishweshshrimali5):

but putting x=y=0 in the eq. gives infinite value

OpenStudy (anonymous):

I don't know then. It's a really tough question in my opinion.

OpenStudy (vishweshshrimali5):

please try to give me some hint so that I can proceed.......

OpenStudy (anonymous):

I really wish I could but you're probably just as good or better at it than I am.

OpenStudy (vishweshshrimali5):

no not at all don't even think that can u tell me ur qualification i have just entered high school

OpenStudy (anonymous):

still you are having problem with it..hey its from trigo nah.. and need to just diffrenciate.

OpenStudy (vishweshshrimali5):

but why should we differentiate it again when it is already

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!