help with calculus
Is that a comma or a y' at the end of that first equation?
it is a coma
So I guess you integrate the first equation, use y(0) = 0 to find the constant, and substitute into the equation to find the answer. Give me a minute to try this
k
I'm finding it really difficult. There doesn't seem to be a good way to simplify it: http://www.wolframalpha.com/input/?i=%28%28cosy+-+2sinx+-+6%29cosx%29%2F%28%28sinx+%2B+4cosy+%2B+2%29siny%29
so what should we do then........
Hmm. I'll keep looking at it and I'll let you know if I come up with anything.
ok thanks
Actually, we're just taking the integral with respect to x right? So I couldn't come up with it myself but wolfram alpha produces this: http://www.wolframalpha.com/input/?i=integral+with+respect+to+x%3A+%28%28cosy+-+2sinx+-+6%29cosx%29%2F%28%28sinx+%2B+4cosy+%2B+2%29siny%29
So substitute (x,y) = (0,0) for the constant and then substitute Pi/2 into the equation.
but putting x=y=0 in the eq. gives infinite value
I don't know then. It's a really tough question in my opinion.
please try to give me some hint so that I can proceed.......
I really wish I could but you're probably just as good or better at it than I am.
no not at all don't even think that can u tell me ur qualification i have just entered high school
still you are having problem with it..hey its from trigo nah.. and need to just diffrenciate.
but why should we differentiate it again when it is already
Join our real-time social learning platform and learn together with your friends!