Question

If a matrix is of order 2x2 & we have to prove its characteristic polynomial of order '3' ,then why does cayley-hamilton theorem does not apply on this question?

Answer 1

please help!

Answer 2

I mean \[|A-\lambda I|\] method.

Answer 3

A n*n has order n polynomial so 2*2 matrix cannot have order 3 characteristic

Answer 4

but I have an ex.

Answer 5

ex?!1

Answer 6

\[[A]=\left[\begin{matrix}2 & 3 \\ 1 & 2\end{matrix}\right]\] & this result holds true:-
\[A^3-4A^2+A=0\]

Answer 7

it is correct and clay hamilton work.try it again you multiply A to side of the equations.

Answer 8

K! thanx a lot !

Answer 9

ok .are you study engineering ?

Answer 10

ya I am doing IIT-JEE coaching

Answer 11

ok be successful

Answer 12

Thanx a lot! but what do u do?

Answer 13

I also studied Control system Engineering.

Answer 14

oh I see ! good luck to u also.

Answer 15

keep in touch i can help you so much!

Answer 16

k! thanx.

Answer 17

your welcome