complete the proof by providing the missing reasons given:cb bisects bd,de bisects ec, cb=de prove dbc=ced CB=DE,CB BISECTS BD AND DE BISECTS EC: GIVEN CBD AND DEC ARE RIGHT ANGLES : DEFINITION OF PERPENDICULAR SEGMENTS CBD=DEC: ? CD=CD: ? DBC=CED : ?
CBD and DEC are right angles by definition of perpendicular segments, therefore CBD=DEC because they are both right angles.
then thats what im going to put because im geting to the point of frustration!
I was hoping @FoolForMath was around, as I recall he was pretty good with geometry.
where is he?
If nothing else put a star by it and come back to it.
Says he's idle in the lobby.
???
Basically unavailable.
danget!
What's your next one?
okay im going to type it its easier i think?
write a paragraph proof to show that ABC=DEC given AC=DC and BC=CE?
You could show that they are congruent triangles using SAS. You are given two sides that are equal and using the rule of intersecting lines you can show that the angles they share are equal.
so is that the proof what you just wrote?? because if so that was easy.
I wouldn't say it was verbatim what I wrote, it has been 20 years since I did geometry so I might not have each rule correctly cited. The overall approach would be similar to what I wrote, yes.
im writing it cause im so frustrated with this math!
lol
Here, it looks to me like you have the last problem on this page: http://library.thinkquest.org/20991/geo/ctri.html
yeah it does lol
like this math is hard :/
The thing with geometry is you basically memorize a bunch of angle theorems and apply them wherever you can.
and i hate that because they all basically sy the same thing over and over so you really dont know which one to choose geometry sucks. and now the rest of the questions are easy. smh.
That's good you found some easy ones, with any luck someone will come along and point out the answer to anything we may have missed here.
.Given: AB is the perpendicular bisector of IK. Name two lengths that are equal.
yeah i hope so i have two tries to get A im using one so i hope i get it the 1st time.
Two lengths that are equal, I would say AK and BI
But how to prove it.
oh man oh man idk idk oh man :((
If it passes through the midpoint of IK, then IJ and JK are equal, which is the definition of a midpoint.
okay thx and umm you know how we have the chat room at the bottom of the screen why is it when i get on there and say can someone help me please some ppl are rude but they really arnt doing anything but talking about nothing i dont get it?
.Li went for a mountain-bike ride in a relatively flat wooded area. She rode for 6 km in one direction and then turned and pedaled 16 km in another. Finally she turned in the direction of her starting point and rode 8 km. When she stopped, was it possible that Li was back at her starting point? Explain.?
Most people see the chat as just that, a chat and try to use it like they would facebook or any other place they chat with friends. It is seldom that you will find help in the chat room and you will find that most people who like to help just troll the question board looking for questions they want to try.
Can you make a triangle with 6,8,16?
yes you can wait no you wait idk i thoght it would have to be odd but a triangle can have any number for sides but it would be obtuse since 16 is really big or no.
a+b >=c So I would need to find the rule, but as I recall your 'a' side plus your 'b' side must be greater than your 'c' side or you cannot make a triangle.
okaay so 6 is first thats a then 16 is b and then 8 is c? so yeah you can but idk if shes back at her starting point.
According to the triangle inequality theorem: http://www.mathwarehouse.com/geometry/triangles/triangle-inequality-theorem-rule-explained.php you cannot have a triangle of 6,8,16, it would look like this:|dw:1336629308084:dw|
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