Question

find acceleration and displacement?

Answer 1

by using the following graph wait i m posting d graph.

Answer 2

acceleration at t=2.4s
' " at t=22.5s

Answer 3

Very well.
you will need to find the acceleration for each segment. if the average acceleration of the whole trip of required, use final velocity-initial velocity by total time.

And 'net' area under the v-t graph gives the displacement. Evaluate that by breaking the graph into triangles rectangle or trapeziums to evaluate it easily.

Answer 4

Displacement, velocity, acceleration
Kinemetics is the description of motion; it concerns only the accurate description of the positions of objects, and the change in their positions. It does not deal with the sources of their motion; we'll discuss dynamics in a few weeks.
Displacement is a vector which points from the initial position of an object to its final position. The standard units of displacement are meters.
Velocity is a vector which shows the direction and rate of motion. The standard units of velocity are meters per second.
Speed and velocity are not the same thing: speed is a scalar, whereas velocity is a vector. One must use different rules when combining speeds and combining velocities.
The average velocity of an object is the total displacement during some extended period of time, divided by that period of time.
Instantaneous velocity, on the other hand, describes the motion of a body at one particular moment in time.
Acceleration is a vector which shows the direction and magnitude of changes in velocity. Its standard units are meters per second per second, or meters per second squared.
Average acceleration is the total change in velocity (magnitude and direction) over some extended period of time, divided by the duration of that period.
Instantaneous acceleration is the rate and direction at which the velocity of an object is changing at one particular moment.
In everyday English, we use the term decelerate to describe the slowing of a body, but physicists use the word accelerate to denote both positive and negative changes in speed.
Viewgraphs

Answer 5

@merchandize 4rm where u hav pasted it

Answer 6

haha lol that was epic fail^

Answer 7

lol

Answer 8

what to do wid it.......is it fine or something else..??

Answer 9

?@apoorvk

Answer 10

???

Answer 11

@apoorvk can u hlp me out by solving this through integration

Answer 12

find acceleration if v=60m/s and t=2.4s

Answer 13

among u all who is seeing this question if u can hlp me then hlp and if u dont know how 2 solve then plz tell

Answer 14

TUKERsdkoiyn miju miuy.

Answer 15

Honestly, you haven't indicated the time in your graph... How can we know when is t=2.4s and t=22.5s?

Answer 16

yeah, you haven't indicated time intervals in the graph.

Answer 17

wait i m posting d proper graph

Answer 18

ruchi no need to pot graph y btao kaha help chiye

Answer 19

find acceleration at t=2.4s,t=4.7,t=7.8,t=10.1,t=12.3,t=20.8,t=22.5.

Answer 20

http://www.twiddla.com/835558 come here ll xplain u

Answer 21

ruchi i ll not solve the whole quetion u have to understand ... OS is not the answer book :/

Answer 22

Okay, done? Or still at sea.

Answer 23

i hav nt asked u solve it totally

Answer 24

hmm i ll solve hald of it how to do rest u have to do urself??

Answer 25

*half

Answer 26

Just we have to find the slope of the velocity time plot at each indicated points..

at t=2.4 acceleration is (60-0)/(4-0)= 15ms^-2
at t=22.5s acceleration is (0-(-36))/(23-22)= 36 ms^-2

the trick in this question isn't about finding the slope but a little thing we have to care is since the lines are straight at every point between 0 to 4 second & at every point between 22 & 23 second the slope & hence the acceleration is same.