Question

the angle of projection with horizontal of a projectile launched upwards from level ground is30 degree the ratio of horizontal range to maximum height is???

Answer 1

we know
R=u^2sintheta2theta/g
Hmax=u^2/2g
by taking ration of both u get
R/Hmax=sin2theta/2
R/hamx=2sin30degree/2
R/hmax=1/2

Answer 2

R/H = 4U/V
where R is horizontal range
H is max height
U =u cos30 is horizontal component of velocity
V=u sin30 is vertical component of velocity
I guess you can proceed further yourself

Answer 3

how r/h=4u/v

Answer 4

sorry now i get it

Answer 5

ok.. :)